fie x cantitatea de peste
primul 2/3 din x = 2x/3
ramane x-2x/3=x/3
al doilea 3/10 din x/3=x/10
al treilea a primit x/3 -x/10= 10x-3x/30=7x/30
primul+al doilea+al treilea
=x
7x/30+143+x/10+7x/30=x
17x/30+143=x
17x+4290=30x
13x=4290
x=330kg peste in total
primul=660/3=220kg
al doilea=330/10=33kg
al treilea=7×330/30=77kg