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Rezolvati sistemele, folosind metoda substitutiei:

{x-2y=1
{y=x+1

{x-y+5=0
{3x-y=-3


VA ROOOOOOG AM NEVOIE DE AJUTOR URGENTTT DAU PUNCTE IN PLUS SI COROANA!!!


Răspuns :

{x-2y=1
{y=x+1

x-2(x+1)=1
x-2x-2=1
-x=3
x=-3
y=-3+1=-2

{x-y+5=0
{3x-y=-3

x=y-5
3(y-5)-y=-3
3y-15-y=-3
2y=12
y=6
x=6-5=1