Pb-2e---> Pb⁺² ori3--> pui 3Pb ,3Pb(NO3)2
N⁺⁵ +3e--> N⁺² ori2---> pui 2NO
-moli NO: n sau niu= V/22,4; n= 2,24l/22,4l/mol= 0,1mol
8mol 3mol 2mol
3Pb+8HNO3---> 3Pb(NO3)2+2NO+4H2O
n=..0,8/2....n=..0,3/2.......0,1mol
m=nxM
m= 0,15mol(207gPb+2x14gN+6X16gO)/mol=...............calculeaza !!!!
c=n/V
0,1=0,4/V...........................calculeaza V(in litri)!!!!!
