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Se considera multimea A={x€Z|-2< sau = 3x+1< sau =8} . Determinati AΠ Z. VA rog repedeeeee......!!!!

Răspuns :

-2≤3x+1≤8
3x+1≥-2
3x≥-3
x≥-1=>x∈[-1,+∞)

3x+1≤8
3x≤7
x≤7/3=>x≤(-∞,7/3]

Intersectia,acestor,domenii,este,solutia:[-1,si,7/3]
[-1,si,7/3]∩Z={-1,0,1,2}