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Fie ABC triunghi dreptunghic, BC=6cm,R=2radical din 3,m(â)=? rezolvare plizzz

Răspuns :

Se aplica teorema sinusurilor: [tex] \frac{AB}{sinC}= \frac{AC}{sinB}= \frac{BC}{sinA} =2R,deci, \frac{6}{sinA}=2R [/tex], deci sinA=[tex] \frac{BC}{2R}= \frac{6}{4 \sqrt{3} } = \frac{ \sqrt{3} }{2},deci [/tex], m(∡A)=60°.