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Simplificati fractia F(x) = x la a 2 a +5x+6 totul supra (x+2) la a 2 a

Răspuns :

[tex]\displaystyle \it F(x)= \frac{x^2+5x+6}{(x+2)^2} = \frac{x^2+2x+3x+6}{(x+2)^2} = \frac{x(x+2)+3(x+2)}{(x+2)^2} = \\ \\ = \frac{(x+2)(x+3)}{(x+2)^2} = \frac{x+3}{x+2} \\ \\ F(x)= \frac{x+3}{x+2} [/tex]