1.
1mol.................................x mol
CnH2n+2 + 3n+2/2 O2 --> nCO2 + (n+1) H2O + Q
0.001mol...............................0.003mol
0.003=0.001x==>x=0.003=3 moli
C3H8-propan
n=V/Vmolar=22.4/22.4=1milimoli=0.001 moli alcan
n=m/M=0.132/44=0.003 moli CO2
2.
14n+2g...............................n*44g
CnH2n+2 + 3n+2/2 O2 --> nCO2 + (n+1) H2O + Q
0.58g..................................1.76g
n=(14n+2)*1.76=44n+0.58==>24.64n+3.52=25.52n==>0.88n=3.52==>n=4
C4H10-butan
n=V/Vmolar=0.896/22.4=0.04 moli
n=m/M==>m=n*M=0.04*44=1.76g
MCO2=44g/mol