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Răspuns :

a) 3(a+b+c)=3·13=39
b) 
5(a+b+c)+12=5·13+12=65+12=77
c) 1
0(a+b+c)-100=10·13-100= 130-100=30 
a+b+c=13
3a+3b+3c=3(a+b+c)=3*13=39
5a+5b+5c+12=5(a+b+c)+12=5*13+12=77
10a+10b+10c-100=10(a+b+c-10)=10(13-10)=10*3=30

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