ma=(a+b+c+d)/4 deci a+b+c+d=16, 5×4=66 (1)
ma=(a+b)/2 deci a+b=7, 5×2=15 (2)
d=2c (3)
a=b+3 (4)
din relatiile (4) si (2)
2b+3=15, 2b=12, b=6
a=6+3=9
in relatia (1) inlocuim ce am aflat si relatia (3)
9+6+c+2c=66
15+3c=66
3c=66-15
3c=51
c=17
d=2c=2×17=34
Numerele sunt: 9, 6, 17 si 34
verificare (9+6+17+34)/4=66/4=16, 5