ΔADB, m<D=90
DB=8√3
Notezi AB=2X
AD=X
(2X)²=X²+(8√3)²
4X²=X²+192
3X²=192
X²=64
X=8
AD=8 cm
AB=16 cm
Construiesti inaltimea DM si aplici th inaltimii in triunghiul dreptunghic ADB
DM=[tex] \frac{AD*DB}{AB} = \frac{8*8 \sqrt{3} }{16} =4 \sqrt{3}
[/tex] cm
Aria=DM*AB
Aria=4√3*16=64√3 cm²
b)
[tex] \sqrt{} \frac{529}{100} = \frac{23}{10} =2,3[/tex]
