a.(x-2)² supra 3 +20supra 3 = (5x+4)(x-3) supra 6 - ((x-5)(x+4) supra 2
2(x^2-2x+1)+40=(5x+4)(x-3)- 3((x-5)(x+4)) // am adus la acelasi numitor
2x^2-4x+2+40=5x^2-15x+4x-12- 3(x^2+4x-5x-20)
2x^2-4x+42=5x^2-11x-12- 3x^2-12x+15x+60
2x^2-5x^2+3x^2-4x+11x+12x-15x=60-12-42
14x=6
x=3/7
b.2x-7 supra 9 - x-5 supra 6 = x-9 supra 8
8(2x-7)-12(x-5)=9(x-9)
16x-56-12x+60=9x-81
4x-9x=-81-4
5x=-85
x=-17
c.5x-3 supra 4 - 9x-1 supra8 =3-3+4x supra 2
2(5x-3) - 9x+1 =16x
10x-6-9x+1=16x
x-5=16x
15x=-5
x=-1/3
