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Daca numerele naturale a,b,c indeplinesc simultan conditiile:
a+b+c≈972
a+b≈c
a:2≈b atunci b+c este:
a.648
b.486
c.162
d.324


Răspuns :

a=2*b
c+c=972
2*c=972
c=486
a+b=c
a+b=486
2*b+b=486
3*b=486
b=486:3
b=162
b+c=162+486=648

a=2*b
c+c=972
2*c=972
c=486
a+b=c
a+b=486
2*b+b=486
3*b=486
b=486:3
b=162
b+c=162+486=648