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Suma a 5 numere consecutive este 40


Răspuns :

a+a+1+a+2+a+3+a+4=40
5a=40-10=30
a=30:5
a=6
6+1=7
6+2=8
6+3=9
6+4=10
6+7+8+9+10=40

Fie n, n+1, n+2, n+3 si n+4-cele 5 nr. consecutive.
n+n+1+n+2+n+3+n+4=40
5n+10=40
5n=40-10
5n=30
n=30/5
n=6=>
Numerele sunt: 6, 7, 8, 9 si 10.