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(4x+1)totul la a doua - (2x+3)totul la a doua

Răspuns :

[tex](4x+1)^{2} -(2x+3)^{2} [/tex]
[tex] (4x+1)^{2}=16 x^{2} +8x+1[/tex]
[tex] (2x+3)^{2}=4 x^{2} +12x+9[/tex]
[tex]16 x^{2} +8x+1-4 x^{2} +12x+9=12 x^{2} +2x+10[/tex]