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rez ecuatia (x+3)(x+5)+(1-x)^2=2(3-x)(3+x)+(2x-1)^2+7

Răspuns :

[tex](x+3)(x+5)+(1-x)^2=2(3-x)(3+x)+(2x-1)^2+7\\ x^2+3x+5x+15+1-2x+x^2=2*(9-x^2)+4x^2-4x+1+7\\ 2x^2+6x+16=18-2x^2+4x^2-4x+8\\ 2x^2+6x+16=26+2x^2-4x\\ 10x=10\\ x=1[/tex]