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Stiind ca x apartine R\ (2;3), calculati 3/x-2 + 2/x-3.
/ inseamna supra.


Răspuns :

3/(x-2)+2/(x-3)= 3(x-3)+2(x-2)= 5x-13 => x=13/5
[tex]^{x-3)} \frac{3}{x-2} +^{x-2)} \frac{2}{x-3} = \frac{3x-9+2x-4}{(x-2)(x-3)} = \frac{5x-13}{(x-2)(x-3)} [/tex]