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a+b+c=nr pare consecutive
daca le adunam la triplul sumei obtinem 528
afla nr


Răspuns :

suma=528:4=132
a+b+c=132
a+a+2+a+4=132
3a=132-6=126
a=126:3
a=42
b=44
c=48
verificare
42+44+46=132
132+132x3=528