[tex]6(x-1)^2=(2+\sqrt{10})\sqrt{14-2\sqrt{40}}\\
2\sqrt{40}=2\sqrt{4\cdot10}=2\cdot2\sqrt{10}=4\sqrt{10}\\
\sqrt{14-4\sqrt{10}}=\sqrt{10+4-4\sqrt{10}}=\sqrt{(2-\sqrt{10})^2}=|2-\sqrt{10}|=\\= \sqrt{10}-2\\
Revenind:6(x-1)^2=(2+\sqrt{10})(\sqrt{10}-2)\\
6(x-1)^2=10-4\\
6(x-1)^2=6|:6\\
(x-1)^2=1\\
|x-1|=1\\
Si\ de\ aici\ avem\ cele\ doua\ solutii....[/tex]
