Ip.: Concluyie:
ABCD= tr. dr. AM= x= ?
A ABCM= A CDM= a
AD= 15 cm
Dem. :
A ABCD= _(B+ b)_ ·h A ABCD= A ABCM+ A CMD
2
A ABCD= _(15+ 7)_· 10 A ABCM= A CMD= a
2
110 cm² = a+ a
A ABCD= (15+ 7)· 5 110 cm²= 2a I : 2
A ABCD= 22· 5 55 cm² = a
A ABCD= 110 cm² A ABCM= A CMD= a= 55 cm²
A ABCM= _(B+ b)_ ·h
2
55 = _(7+ x)_ ·10
2
55 = (7+ x)· 5 I : 5
11 = 7+ x
11- 7= x
4 cm= x= AM