[tex]\displaystyle \\
\frac{2}{ \sqrt{3}-1 } -\sqrt{3} = \frac{2}{ \sqrt{3}-1 } - \frac{\sqrt{3}(\sqrt{3}-1 )}{ \sqrt{3}-1 } = \\ \\ \\
=\frac{2-\sqrt{3}(\sqrt{3}-1 ) }{ \sqrt{3}-1 } = \frac{2-(3-\sqrt{3}) }{ \sqrt{3}-1 } = \\ \\ \\
= \frac{2-3+\sqrt{3} }{ \sqrt{3}-1 } = \frac{-1+\sqrt{3} }{ \sqrt{3}-1 } = \frac{\sqrt{3} -1 }{ \sqrt{3}-1 } = \boxed{1 } \\ \\ \texttt{cctd}[/tex]