[tex]\displaystyle \\
x^2 = 1+3+5+ \hdots +101 \\
\texttt{Calculam numarul termenilor sumei (n)}. \\ \\
n= \frac{101-1}{2}+1 = \frac{100}{2}+1 = 50 + 1 = 51~de ~termeni \\ \\
x^2 = \frac{51(101+1)}{2} \\ \\
x^2 = \frac{51 \times 102}{2} \\ \\
x^2 = 51 \times 51 \\ \\
x^2 = 51 ^2 \\ \\
x = \sqrt{51^2} = \boxed{51}
[/tex]
