n1 CH4 + Cl2 ⇒ CH3Cl + HCl
n2 CH4 +2Cl2 ⇒ CH2Cl2 + 2HCl
n3 CH4 nereactionat
n1/ 4 = n2/ 3 = n3/ 1 = n/8 ⇒ n1 = n/2 n2 = 3n/8 n3 = n/8
nHCl = n1 + 2n2 = n/2 + 3n/4 = 5n/4
nCl2 = n1 + 2n2 = 5n/4
b) nCH4 / nCl2 = n·4/5n = 4/5
sol. HCl : Vs = 5 l Cm = 4mol/ l ⇒ nHCl = 20moli
5n/4 = 20 ⇒ n = 16 moli CH4 pur V = 16·22,4 = 358,4 l
V cu imp. = 358,4·100/99 = 362 l