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sa se calculeze de moli si de molecule ce se gasesc in 500 g de oxid de aluminiu

Răspuns :

M Al2O3 = 2*27 + 3*16 g/mol = 54+48 = 102 g/mol

1 mol ... 102 g ... 6.023*10^23 molecule
x mol ... 500 g ... y molecule

x=500/102 = 4.9 moli
y= 29.52*10^23 molecule