[tex]3x^2+13x-10=0 \\ \Delta=b^2-4ac\\ \Delta=13^2-4\cdot3\cdot(-10)\\ \Delta=169+120 \\ \Delta=289 \\ \\\boxed{ X_1= \frac{-b- \sqrt{\Delta} }{2a} = \frac{-13-17}{2\cdot3} = \frac{-30}{6} =-5} \\ \boxed{ X_2= \frac{-b+\sqrt{\Delta} }{2a} = \frac{-13+17}{2\cdot3} = \frac{4}{6} = \frac{2}{3} } \\ \\ \\ \boxed{\boxed{S=\{ -5 ; \frac{2}{3} \}}} \\ [/tex]
