a)[tex]2arcsinx- \pi =0,sau,arcsinx= \frac{ \pi }{2},aplic,"sin",rezulta,sin(arcsinx)[/tex]=[tex]sin \frac{ \pi }{2},deci,x=1. [/tex]
b)Avem de fapt ec.: [tex]arccos \sqrt{x} = \frac{ \pi }{6},aplic,"cos",rezulta,cos(arccos \sqrt{x} )=cos \frac{ \pi }{6},deci, \sqrt{x} = [/tex][tex] \frac{ \sqrt{3} }{2},sau,x= \frac{3}{4} [/tex]
