C₃H₈ + 5O₂--> 3CO₂ + 4H₂O +Q
C₄H₁₀ + [tex] \frac{13}{2} [/tex]O₂--> 4CO₂ + 5H₂O +Q
72 ml = 0.072 L
20 ml = 0.02 L
nr moli CO₂ = [tex] \frac{0.072 }{22.4} [/tex] = 0.0032 moli CO₂
nr moli amestec = [tex] \frac{0.02 }{22.4} [/tex] = 0.0009 moli amestec
1 mol C₃H₈ ................. 3 moli CO₂
x mol C₃H₈ ................. a moli CO₂ =>
=>x= [tex] \frac{a }{3} [/tex]
1 mol C₄H₁₀ ................. 4 moli CO₂
y mol C₄H₁₀ ................. b moli CO₂ =>
=>y= [tex] \frac{b }{4} [/tex]
[tex]\left \{ {{ \frac{a }{3} + \frac{b }{4} = 0.0009 } \atop {a+b = 0.0032}} \right.[/tex]
[tex] \left \{ {{4a + 3b = 0.0108} \atop {a + b = 0.0032 | *(-3)}} \right. [/tex]
[tex] \left \{ {{4a + 3b = 0.0108} \atop {-3a -3b = -0.0096}} \right. [/tex]
a / = 0.0012
a = 0.0012 moli CO₂ din C₃H₈
a + b = 0.0032 => b = 0.002 moli CO₂ din C₄H₁₀
x = [tex] \frac{a}{3} [/tex] => x = 0.0004 moli C₃H₈
y = [tex] \frac{b}{4} [/tex]=> y = 0.0005 moli C₄H₁₀
0.0009 moli amestec ............0.0004 moli C₃H₈
100 .......................................x => x = 44.44% C₃H₈
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