A) Ca(OH)2 + CO2 = CaCO3 ↓ + H2O
B) υ (Ca(OH)2)= υ (CO2)=10moli
m(Ca(OH)2)= υ x M =10moli x 74g/mol=740g
m(sol)=m(sub) x 100% /ω= 740g x 100% / 2% = 37000g= 37 kg
C) Ca(OH)2 + 2HCl = CaCl2 + H2O
υ (HCl)=υ (Ca(OH)2) x 2= 10moli x 2=20 moli
Răspuns: m(sol Ca(OH)2)= 37 kg; υ (HCl) =20 moli