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[(-2)²]³
(-2⁻²)³
Va rog rezolvarile complete dau coronita


Răspuns :

a) [(-2)²]³= [(-2)*(-2)]³ = 4³=4*4*4=64
sau conform regulei
(a^n)^m=a^(nm)
[(-2)²]³=(-2)^(2*3)=(-2)^6=64

b) (-2`²)³=-2`²*³=-2^-6=1/2^6=1/64