V= 84x10⁻³ ml
n= 84ml/22,4ml/mmol= 3,75mmol
ecuatiile reactiilor
CH3-C(CH3)=CH2 + 2O---> CH3-C(CH3)-CH2
i l
OH OH
2KMnO4 +H2O-->2MnO2+2KOH+3O
din prima ecuatie, se deduce
1mol izobutena.......................2mol O
3,75mmol..............................n=7,5mmol O
din a doua ecuatie,
3mmolO........2mmolKMnO4
7,5mmol..........n=5mmol---------------------> C
