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Descompuneți in factori : (4x+1)²-(2x+3)²

Răspuns :

(4x+1)²-(2x+3)² =16x²+8x+1-4x²-12x-9=12x²-4x-8=4(3x²-x-2)
= ( 4x + 1 + 2x + ) x ( 4x + 1 - 2x - 3 ) =
= ( 6x + 4 ) x ( 2x - 2 ) = 
= 2 x ( 3x + 2 ) x 2 x ( x - 1 ) = 
= 4 ( 3x + 2 ) x ( x - 1 )