Vs1=280ml
ro= 1,12g/ml--------> m,s1= Vxro= 280mlx1,12g/ml= 313,6g
c1=36,5----> 36,5/100= md1/ ms1
36,5/100= md1/313,6---> md1=114,46g
-in sol 2 ramane aceeasi masa didolvata, md1=md2=114,46 dar se mareste ms2
ms2=ms1+m,apa= 313,6+300
c2= 114,46x100/613,6------------------------> calculeaza