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Sa se rezolve ecuatia: [tex] 4^{n!} =64*2^n[/tex]
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Răspuns :

4^n! = 4^3 * 2^n

4^n! = (2^2)^3 * 2^n
4^n! = 2^6 * 2^n
4^n!= 2^(6+n)
(2^2)^n!= 2^(6+n)
2^2n!=2^(6+n) => 2n!=6+n => n!=6/2 +n/2 => n!=3+n/2