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Cum se rezolva:9+2×[(2×9×2-2×9)÷9+(99÷9+68)]÷9=

Răspuns :

rezolvi mai intai parantezele mici
9+2x[18:9+79]:9=9+2x81:9=9+162:9=9+18=27
=9+2×(18÷9+79)÷9
=9+2×81÷9
=9+162÷9
=9+18
=27
Coronita?