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Rombul ABCD, cu AC Ω BD= {O} are Aво= 108cm². stiind ca BD= 3supra8 AC, calculati aria rombului

Răspuns :

Aromb=4x108=432 cm²
AC=x
BD=3x/8
Aromb=AC × BD/2
432=(x × 3x/8)/2
3x²/8=864
3x²=6912
x²=2304
AC=x=48 cm
BD=3*48/8=18 cm