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Mihai si Dan au impreuna 78 de abtipilduri.Mihai are cu 16 abtipilduri mai putin decat Dan .Cate abtipilduri are fiecare baiat?Sa se afle prin segmente.

Răspuns :

78-16=62
62:2= 31
31 Mihai
31+16=47 Dan

31+47=78
   

     31
-------------- ----,
,,,,,,,,31,,,,,,,,,,,,,,,,/ ,,,+16,,,,,,,,,       
Dan are un segment, Mihai are un segment plus 16 egal 78 . Faci 78-16 = 62. Faci 62 :2 = 31 (abtipilduri are Dan ) 31+16 = 47 ( mihai )