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log5 (3x+1)=1+log5 (x-1)

Răspuns :

[tex]\it \log_5(3x+1) = 1 +\log_5(x-1)\Rightarrow \log_5(3x+1) = \log_55 +\log_5(x-1) [/tex]

[tex]\log_5(3x+1) = \log_5 5(x-1) \Rightarrow 3x+1= 5x-5 \Rightarrow \ x =3[/tex]