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[tex] \frac{x-9}{3}+ \frac{x-3}{4}+1= \frac{x+12}{12} [/tex]

Va rog frumos!!!


Răspuns :

(x-9)3+(x-3)/4+1=(x+12)12     nmc12
4x-36+3x-9+12=x+12
7x-x=12+24
6x=36
x=36/6
x=6