[tex]4^{x+2}+4^{y-3} \leq 2^{x+y} \\ \\ 4^{x+2}-2^{x+y}+4^{y-3} \leq 0 \\ \\ {(2^{x+2})^2}-2 \cdot 2^{x+2} \cdot 2^{y-3}+(2^{y-3})^2 \leq 0 \\ \\ (2^{x+2}-2^{y-3})^2 \leq 0 \Rightarrow 2^{x+2}=2^{y-3} \Rightarrow x+2=y-3 \Rightarrow~y=x+5. \\ \\ Deci~inecuatia~admite~o~infinitate~de~solutii~de~forma \\ \\ (x;y)=(x;x+5)...[/tex]
