a = [tex]( 2\sqrt{2} [tex]+ \sqrt{2} [/tex] )[/tex] × [tex] (3\sqrt{3} - \sqrt{3} )[/tex] = [tex] 3\sqrt{2} [/tex] × [tex]2 \sqrt{3} =6 \sqrt{6} [/tex]
b = [tex] \sqrt{24} [/tex] + [tex] 2\sqrt{150} : ( \sqrt{2} +4 \sqrt{2} -3 \sqrt{2} ) = [/tex] = [tex](2 \sqrt{6} + 10 \sqrt{6} ): 2\sqrt{2} =12 \sqrt{6} :2 \sqrt{2} =6 \sqrt{3} [/tex]
[tex](a \sqrt{2} ):b = 6\sqrt{12} : 6\sqrt{3} = \sqrt{4} =2[/tex]
2 ∈ N
