1)
f.gen: CnH2n+2
14n+2 g.............................................18(n+1) g
CnH2n+2 + (3n+1)/2 O2 -> nCO2 + (n+1)H2O
46,4g....................................................72g
14n+2=46,4*18*(n+1)/72=11,6(n+1)=11,6n+11,6
2,4n=9,6 => n=4
corect ar fi 3), dar daca e complement grupat, iei 1,2,3
2)
consideram raportul molar metan:propan=x:y
mmetan=16x, mpropan=44y
16x+44y.........100%
12x+36y...........80%
16x+44y=12*100*(x+3y)/80=15x+45y => x=y => raportul este 1:1