a) x=[tex] \sqrt{288} = 12\sqrt{2} [/tex] ( am scos radicalul ; 288=[tex] 12^{2} x2[/tex])
y =[tex] \sqrt{162} = 9\sqrt{2} [/tex] ( 162=[tex]9^{2} x2[/tex] )
media geometrica =[tex] \sqrt{xy} [/tex]
dar xy=[tex]12 \sqrt{2} x 9 \sqrt{2} =12x9x2=216[/tex]
asadar , media geometrica = [tex] \sqrt{216} [/tex]=[tex]6 \sqrt{6} [/tex]
b)-3x+1=7
-3x=6
x= - 2 ∈ R
